Hi Mike, I agree that this example is confusing. There are two event expressions, but the second event expression uses reset which appears in the body(and therefore violates 3b), so there is only one event expression that meets 3a AND 3b. I guess the real question is whether (event1 or event2) is viewed as one event or two events. I personally think this is too complex to expect the tool to extract the clock though. Lisa _____ From: owner-sv-ac@server.eda.org [mailto:owner-sv-ac@server.eda.org] On Behalf Of Mirek Forczek Sent: Monday, December 22, 2008 1:26 PM To: sv-ac@server.eda.org; sv-sc@server.eda.org Subject: [sv-ac] assertion clock inferrence example with comment contradicts the given rules ? Hi, I've noticed a following issue in 16.15.6 Embedding concurrent assertions in procedural code: There are assertion clock inferrence rules given: A clock shall be inferred for the context of an always or initial procedure that satisfies the following requirements: 1) There is no blocking timing control in the procedure. 2) There is exactly one event control in the procedure. 3) Within the event control of the procedure, there is exactly one event expression that satisfies both of the following conditions: a) The event expression is of the form edge_identifier expression1 [ iff expression2 ] and is not a proper subexpression of an event expression of this form. b) No term in expression1 appears anywhere else in the body of the procedure. and an example with comment: Another, more complex example that is legal is as follows: property r3; (q != d); endproperty always_ff @(posedge clock iff reset == 0 or posedge reset) begin r1 <= reset ? 0 : r1 + 1; q <= $past(d1); r3_p: assert property (r3); end In the example above, the inferred clock is posedge clock iff reset == 0. The inferred clock is not posedge clock because posedge clock is a proper subexpression of posedge clock iff reset == 0. But the event control in example: @(posedge clock iff reset == 0 or posedge reset) seems to violate: - rule 3) in general: "there is exactly one event expression" - here we have 2 event expressions ("posedge clock iff reset == 0" and "posedge reset") I guess, otherwise what would be an example of more than one event expressions that would violate the rule ? - and in particular: rule 3a): the event expression here is more complex (includes "or" operator) and thus it does not fit the "edge_identifier expression1 [ iff expression2 ]" form. Considering above: no clock shall be inferred in the example or the example code shall be changed (?). Regards, Mirek -- This message has been scanned for viruses and dangerous content by <http://www.mailscanner.info/> MailScanner, and is believed to be clean. -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.Received on Mon Dec 22 20:34:04 2008
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