[sv-ac] P1800-2009 Page 350 "threads do not have to have consistent valuations for the local variables"

Below is LRM statements with highlighted points of concern or
clarification:
LRM states that These threads do not have to have consistent valuations for
the local variables.
But, example does show a consistent valuation for "x".   According to those
rules, the following example would pass the LRM requirements, but I think
that it should not:
sequence s6_MODIFIED_SLIGHTLY;
int x,y;
((a ##1 (b, x = data, y = data1) ##3 c && x==10 )  // Thread1:
or (d ##2 (`true, x = data) ##3 (e==x))) ##1 (x==data2);  // Thread2:
// legal because x is in the intersection
endsequence
Assume a==d==b==1
@ cycle 2, ##1 (b, x = data) causes x=data @ cycle2 for thread 1
(x==dataT1@cy2 // data thread1 @ cycle2)
@ cycle 3, ##2 (`true, x = data) causes x=data @ cycle3. (x==dataT2@cy3)
This is different than what thread1 expects later on.
Thus, Thread 1 now has a different value of x , the one written at cycle 2,

@ cycle 5 (c && x==10), we're expecting x to be 10, the value thought to
have been captured at cycle 2 (i.e., dataT1@cy2),
but x was re-evaluated at cycle 3 with the value dataT2@cy3.
Thus, the rule "These threads do not have to have consistent valuations for
the local variables."
does not stand.  In your LRM example, x is updated in both threads at cycle
2 with the same data if a==b==d==1.
So here it works.  The only way I see the statement "These threads do not
have to have consistent valuations for the local variables".  to be true is
if there are 2 versions of the local variable x, one for each thread.  I
don't believe that this is the intent.
Comments?
Thanks for clarifying this.

------------------------------------------------LRM ------------------------
c) Each thread for an operand of an or that matches its operand sequence
continues as a separate
thread, carrying with it its own latest assignments to the local variables
that flow out of the composite
sequence. These threads do not have to have consistent valuations for the
local variables. For
example:
sequence s5;
int x,y;
((a ##1 (b, x = data, y = data1) ##1 c)
or (d ##1 (`true, x = data) ##0 (e==x))) ##1 (y==data2);
// illegal because y is not in the intersection
endsequence
sequence s6;
int x,y;
((a ##1 (b, x = data, y = data1) ##1 c)
or (d ##1 (`true, x = data) ##0 (e==x))) ##1 (x==data2);
// legal because x is in the intersection
endsequence

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