What should happen if I can't infer an enabling condition or clock, for example: always @(posedge mclk) begin case (a) 1: begin @(negedge clk) b <= c; r4_p: assert property (r4); end default: d <= c; endcase end Is this an error if I have defined a default clock? In other words, am I not allowed to have this or does it simply mean that I can't infer the clock and enabling condition? In 1737, we have only shown 'nice' cases. lisa -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.Received on Thu Jan 10 15:35:39 2008
This archive was generated by hypermail 2.1.8 : Thu Jan 10 2008 - 15:36:24 PST