LRM 18.7.3 does not fully specify the return value of $past when the optional "expression2" is used. It states: ------------- When expression2 is specified, the sampling of expression1 is performed based on its clock gated with expression2. For example, always @(posedge clk) if (enable) q <= d; always @(posedge clk) assert (done |=> (out == $past(q, 2,enable)) ; In this example, the sampling of q for evaluating $past is based on the clocking expression ------------- There are two ambiguities, at least in how I read the LRM. First is the statement "the sampling of expression1 is performed based on its clock gated with expression2". Is the gating based on the current sampled value of expression2, or the sampled value of expression2 at the specified number of clock ticks in the past? Second, since $past is a function, and can also be called from procedural code, it must return a value for when the enabling expression is either true or false. The return value for when expression2 is true is clear, but the LRM does not define the return value for when the enabling expression is false. At least I didn't find a definition. Does anyone know the answers to these questions? Thanks, Stu ~~~~~~~~~~~~~~~~~~~~~~~~~ Stuart Sutherland stuart@sutherland-hdl.com +1-503-692-0898Received on Thu Apr 14 01:28:22 2005
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